Length of circular track is:
L = 2*r*pi
He run 3/4 of it so length is:
L' = 3*2/4*r*pi = 3/2*r*pi
To calculate speed of his movement we use formula:
v = s/t where s = L' and t = 1 minute 45 seconds = 105 seconds
v = L'/t = 3*r*pi/2*105
v = r* pi/70
If we take that r = 1
answer
Answer:
3 units or 3/1 (the fraction)
Step-by-step explanation:
Do 3/4 x 3 and you got 12/4 and that is simplified to 3
Step-by-step explanation:
7. ∆ABC = ∆ILH by SSS
as, AB = IL , BC = LH , CA = HI
8. ∆DEF = ∆AMS by ASA
as , angle D = angle A, EF = MS , angle F = Angle S
9. ∆JKL = ∆HAT by SAS
as, JK = HA , KL = AT , angle L = angle T
10. ∆ABC = ∆KPG by ASA
as , CA = GK, Angle c = angle G and Angle B = angle P
11. ∆ABC = ∆YDE by ASA
as , angle A = angle Y, AB = YD , angle B = angle D
12. ∆MNO = ∆SAK by ASA
as , Angle M = angle S, NO = AK, angle O = angle K
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I think you have to make 4 1/3 into an improper fraction that is 13/1 because 4*3=12 12+1=13. Then you divided 13/1(on a calculator you get a decimal) your will be 1 3/11