Start with the simplest equation of a straight line: y = mx + b.
Subst. 1 for m, 2 for x and 4 for y. Then, 4 = 1(2) + b, or b = 2.
In slope-intercept form, the equation of this line is y = x + 2.
Answer:
d.) simplify the expression inside the pipe symbols
Answer:
71°
142°
Step-by-step explanation:
![\because QS \: is \: the \: bisector \: of \: \angle \: PQR\\\therefore m\angle RQS =m\angle PQS\\\because m\angle RQS = 71\degree...(given) \\ \huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\ \because \: m\angle \: PQR = m\angle PQS + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree + 71\degree \\ \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}](https://tex.z-dn.net/?f=%20%5Cbecause%20QS%20%5C%3A%20is%20%5C%3A%20the%20%5C%3A%20bisector%20%5C%3A%20of%20%5C%3A%20%20%5Cangle%20%5C%3A%20PQR%5C%5C%3C%2Fp%3E%3Cp%3E%5Ctherefore%20m%5Cangle%20RQS%20%3Dm%5Cangle%20PQS%5C%5C%3C%2Fp%3E%3Cp%3E%5Cbecause%20m%5Cangle%20RQS%20%3D%2071%5Cdegree...%28given%29%20%5C%5C%3C%2Fp%3E%3Cp%3E%20%5Chuge%20%5Cred%7B%20%5Cboxed%7B%5Ctherefore%20m%5Cangle%20PQS%20%3D%2071%5Cdegree%7D%7D%20%5C%5C%20%20%20%5Cbecause%20%5C%3A%20m%5Cangle%20%5C%3A%20PQR%20%3D%20m%5Cangle%20PQS%20%20%2B%20m%5Cangle%20RQS%20%5C%5C%20%5Cbecause%20%5C%3A%20m%5Cangle%20%5C%3A%20PQR%20%3D%2071%5Cdegree%20%2B%20%2071%5Cdegree%20%5C%5C%20%20%5Chuge%20%5Cpurple%7B%20%5Cboxed%7B%5Ctherefore%20%5C%3A%20m%5Cangle%20%5C%3A%20PQR%20%3D%20142%5Cdegree%7D%7D)
Answer:
I am pretty sure it is 53cm.
Step-by-step explanation:
If it were in a cylinder shape 10 x 8 is 80 but is is in the shape of a cone so the volume lessens so it can't be 80cm or 160cm. 27cm is a bit to low so that is why I am 90% sure it is 53cm.