1.5 more than the quation of a and 4 is b

Mathematics

2 answers:

Zarrin [17]2 years ago

8 0

I hope this helps you

1,5+a+4=b

5,5+a=b

Kruka [31]2 years ago

3 0

I think it is (a+4=b)+1.5

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Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

2 years ago

Please please please

sergiy2304 [10]

Sorry can see good in the pic maybe next time
Sorry

8 0

2 years ago

2*cosx*(2x+30°) + √3=0

MAXImum [283]

Answer: x ≈ 1.59688927, −1.60312387, −4.67045686, 4.69039614, 7.872914, −7.91513776, −10.89002194

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

Simplify 2*cosx*(2x+30°) + √3=0

Simplify each term.

Apply the distributive property.

2 cos ( x ) ( 2 x ) + 2 cos ( x ) * 30 ° + √ 3 = 0
Multiply 2 by 2
4 cos ( x ) x + 2 cos ( x ) *30 ° + √ 3 = 0
Multiply 30 °by 2
4 cos ( x ) x + 60 cos ( x ) + √ 3 = 0
Reorder factors in 4 cos ( x ) x + 60 cos ( x ) + √3
4xcos(x)+60cos(x)+√3=0
Graph each side of the equation. The solution is the x-value of the point of intersection. x ≈ 1.59688927 , − 1.60312387 , − 4.67045686 , 4.69039614 , 7.872914 , − 7.91513776 , − 10.89002194