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kupik [55]
4 years ago
12

Lissette 's age is 3 years less than twice the age of her sister Francesca. Lissette is 13. Write an equation that can be used t

o find Francesca's age
Mathematics
2 answers:
mylen [45]4 years ago
8 0
Answer Is 8 not 5 16/2 = 8
PilotLPTM [1.2K]4 years ago
3 0
Let l= lisette's age and f=francesca's age

L=2f-3
L=13
so 13=2f-3
solve to get f=5
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You should start with a simple equation. And remember- practice makes perfect.

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6 0
3 years ago
Please help me find out what the question marks are
quester [9]
Question a

g(x) times \sqrt{x-5}=\sqrt{x^2-5}
divide both sides by √(x-5)
g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}
g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}
g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}


question b
g(x) \space\ times \space\ 1+\frac{1}{x}=x
divide both sides by 1+1/x
g(x)=\frac{x}{1+\frac{1}{x}}
times by x/x
g(x)=\frac{x^2}{x+1}


question c
\frac{1}{x} \space\ times \space\ f(x)=x
times both sides by x
f(x)=x^2


question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})
so f(x)=√x


a. g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}
b. g(x)=\frac{x^2}{x+1}
c.f(x)=x^2
d. f(x)=\sqrt{x}
3 0
4 years ago
Read 2 more answers
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