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Gennadij [26K]
4 years ago
13

A rectangular room 14 feet by 12 feet has a semicircular sitting area attached with a diameter of 12 feet. What is the total are

a of the room and the sitting area?
Mathematics
1 answer:
madam [21]4 years ago
3 0
The total area in this case will be given by the sum of the two areas: rectangular plus semicircular. We have then:
 A = (14) * (12) + (pi / 2) * (6 ^ 2) = 224.55 ft ^ 2.
 the total area of the room and the sitting area is 224.55 ft ^ 2.
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Select all expressions that are equivalent to (2n+6)(n+3)
eduard

Answer:

(2n+6)(n+3)=

(2*n+2*3)(n+3)=

2(n+3)(n+3)=.....(1)

2(n+3)^2=....(2)

2(n^2+2*n*3+3^2) =

2(n^2+6n+9)=....(3)

2n^2+2*6n+2*9=

2n^2+12n+18.... (4)

6 0
3 years ago
IN A SHOP THE NORMAL PRICE OF A JACKET IS $60 . THE COST OF THE JACKET IN A SALE IS 3 BY 4 OF THE NORMAL PRICE
kramer

Answer:

$45

Step-by-step explanation:

3/4×60= 45

cost of jacket in sale: $45

hope it helps!

5 0
3 years ago
What is the quadric regression equation that fits these data
Angelina_Jolie [31]
Where’s the data?................
6 0
3 years ago
A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.
IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car (v_0) = 40 ft/sec

Deceleration of the car (\frac{dv}{dt}) = -10 ft/sec²

Final speed of the car (v_x) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, \frac{dv}{dt}=-10\ ft/sec^2

Negative sign means the velocity is decreasing with time.

Now, \frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt}) using chain rule of differentiation. Therefore,

\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft

Therefore, the car travels a distance of 80 feet before stopping.

4 0
3 years ago
If an archer shoots an arrow straight upward with an initial velocity of 160
HACTEHA [7]

Answer:

maximum height of the arrow will be 408 m

Step-by-step explanation:

We have given the function of height as h(t)=-16t^2+160t+8

We know that first derivative of height will be velocity

So first derivative of height

\frac{dh}{dt}=-32t+160

v(t)=-32t+160

We know that at maximum height velocity will be zero

-32t+160=0

t = 5 sec

Sp arrow will be at maximum height at t = 5 sec

So height at t = 5 sec will be

h(5)=-16\times 5^2+160\times 5+8=408m

So maximum height of the arrow will be 408 m

5 0
3 years ago
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