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3 years ago

Algebra Need Help Pls. Can someone explain to me how to do this?

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

Answer:

y=-3x

Step-by-step explanation:

Mark me as brainliest

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Find the probability that the person is frequently or occasionally involved in charity work.

Schach [20]

Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

$\begin{tabular}
{|c|c|c|c|c|c|}
 &Frequently&Occassionally&Not at all&Total\\[1ex]
Male&227&454&798&1,479\\
Female &205&450&747&1,402\\
Total&432&904&1,545&2,881
\end{tabular}$

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

$P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}$

Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

$P(being
 \ female \ or \ not \ being \ involved)\\ \\= 
\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = 
\frac{2200}{2881}=\bold{0.764}$

Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

$P(being
 \ male \ or \ being \ frequently \ involved)\\ \\= 
\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = 
\frac{1684}{2881}=\bold{0.585}$

Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

$P(being
 \ female \ or \ not \ being \ frequently \ involved)\\ \\= 
\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = 
\frac{2654}{2881}=\bold{0.921}$

Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".

4 0

2 years ago

A cylindrical cardboard mailing tube has a diameter of 5 in. and a height of 30 in. A total of 30% of the tube’s capacity is fil

olga2289 [7]

First is to get the volume of the cylinder.
Volume = pi * r^2 * H
Volume = 3.1416 * (5/2)^2 * 30
Volume = 589.05 in^3

30% is already filled.
Filled Space = 589.05 * 0.30
Filled Space = 176.715 in^3
Empty Space = 412.335 in^3

Next, get the volume of the sphere.
V = (4/3)*pi*r^3
V = (4/3)*pi*(0.6/2)^3
V = 0.1130976 in^3

Number of foams = Filled Space / V
Number of foams = 176.715 / <span>0.1130976
Number of foams = 1562 Foams</span>

5 0

3 years ago

Which vocabulary is used to explain out of control conditions on a chart ?

horsena [70]

An odd or far from average result on a graph or chart is called an outlier.

3 0

3 years ago

I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t

belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

$\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}$

Where

$\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}$

Thus,

$\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}$

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

$\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}$

Thus, from the theorem of similar triangles,

$\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}$

solving for y, we have

$\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}$

thus, YC = 10.

4 0

1 year ago

10 The table shows the cost of blueberries at a local farmer's

egoroff_w [7]

Answer:

This question needs rephrasing. It makes no sense.

Step-by-step explanation:

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3 years ago