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uysha [10]
3 years ago
8

BRAINLIEST

Mathematics
2 answers:
lina2011 [118]3 years ago
4 0
First you find the unit rate for (2, 7). You divide y by the x so-ooo 7 ÷  2 = 3.5. Next you multiply the unit rate, 3.5, by 5 to get 17.5. Your answer is 17.5. I took a test with this question and that was the answer, in case you need assurance.

Hope this helps,
♥Nikki♥
masha68 [24]3 years ago
3 0
17.5 hope it helped !!!
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Michael wants to plant a circular flower garden in his backyard. If the radius of his garden is 12.5 feet, what is the circumfer
MrRa [10]
12.5 x 2 (you need the diameter to find pi) =25pi ft
6 0
3 years ago
Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation
Anestetic [448]

Answer:

27 hours

Step-by-step explanation:

Just do the reverse. 65-11 = 54. 54 / 2 = 27.

5 0
3 years ago
the sum of the measurement of two angles is 183.61 angle one has a measure of 54 what is the measure in degrees of the second an
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3 years ago
Assume that a sample is used to estimate a population proportion μ . Find the margin of error M.E. that corresponds to a sample
hichkok12 [17]

Answer:

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Step-by-step explanation:

Since the sample size is quite large, we can use the z-distribution.

The margin of error is  given by

$ MoE = z_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where n is the sample size, s is the sample standard deviation and z_{\alpha/2} is the z-score corresponding to a 90% confidence level.

The z-score corresponding to a 90% confidence level is

Significance level = α = 1 - 0.90= 0.10/2 = 0.05

From the z-table at α = 0.05

z-score = 1.645

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Therefore, the margin of error is 0.776.

3 0
3 years ago
A construction company delivered 40 loads of concrete in 5 days.
AnnZ [28]
Well 40 divided by 5 is 8 and you don't have options so I would say 8 loads a day :)
3 0
3 years ago
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