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Liono4ka [1.6K]
3 years ago
12

PLEASE ANSWER GIVING 30 POINTS

Mathematics
2 answers:
Orlov [11]3 years ago
8 0

Answer:

this is only 15points but ok

Step-by-step explanation:

answer: D)

vodomira [7]3 years ago
6 0

Answer:

The answer should be 15.

Step-by-step explanation:

\sqrt[3]{125} Factor 125 = 5^{2} x 5. Rewrite the square root of the product \sqrt{5^{2}X5 }  as the product of square roots. \sqrt{5^{2} }   \sqrt{5}. Take the square root of 5^{2}.

3 x \sqrt[5]{5} Multiply 3 and 5 to get 15.

\sqrt[15]{5}

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If f(x)=x^2-2x-8 and g(x)=1/4x-1, for which value of x is f(x)=g(x)?
Umnica [9.8K]

Answer:

The answer is 4

Step-by-step explanation:

x^2-2x-8=1/4x-1

x^2-9x/4-7=0

4x^2-9x=28

Therefore if we take value of x as 4 aur eq.get balanced...

3 0
3 years ago
Write the phase as an expression.<br><br> 10 less than the quotient of 24 and a number t
irina1246 [14]

Answer:

24/t-10

Step-by-step explanation:

So its quotient so 24/t, and minus 10 becuase less than

7 0
3 years ago
Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aliina [53]

Answer:

16

Step-by-step explanation:

Solve 5 to the power of x minus 3 to the power of x when x=2.

So, you do 5 to the power of 2 minus 3 to the power of 2, which is 25-9=16

8 0
3 years ago
Read 2 more answers
Helppppp : 5×(2-x)+9-7x
TEA [102]
<span>5×(2-x)+9-7x
=5</span>×2-5<span>×x+9-7x
=10-5x+9-7x
=10+9-(5x+7x)
=19-12x

That's your solution. ^_^</span>
4 0
3 years ago
Read 2 more answers
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
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