Answer:
The answer to your question is: ![\sqrt[4]{2^{3} } + 1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E%7B3%7D%20%7D%20%2B%201)
Step-by-step explanation:
![\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B2-%201%7D%7D%20%20x%20%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%20%2B%201%7D%20%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%5Btex%5D%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B2%20-%201%7D)
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Answer:
12 ft and 25 ft
Step-by-step explanation:
a part is x ft and the other is (2x+1) ft
so 37= x + 2x+1
37= 3x+1
-1 -1
36= 3x
:3 :3
x= 36:3
I= x= 12 ft
II= 2x+1=2*12+1=25 ft
Answer:
pls be more cleare
Step-by-step explanation:
type the question properly and clearly
First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)
nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165
This will be used in the formula below
Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624
The final answer here is choice C) -624
<span>
</span>
Answer:
Step-by-step explanation:
first we gotta find the slope of the first line
(-4,-3),(4,1)
slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2
so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :
1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope
y - y1 = m(x - x1)
slope = -2
(-4,3)...x1 = -4 and y1 = 3
now sub
y - 3 = -2(x - (-4) =
y - 3 = -2(x + 4) <=====
