Answer:
3 times
Step-by-step explanation:
Firstly we calculate the number of minutes between 8 and 11 am
The number of hours is 3 hours
The number of minutes is 180 minutes since 1 hour is 60 minutes
Now out of 180, to know the number of times that they both leave, we need to get the multiples of both between 0 and 180
The multiples are;
60, 120, 180
This means that they leave together 3 times
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Perpendicular lines have the negative reciprocal slope, so the slope of your new line will be -1/4 and the current equation will be as follows:
y = -1/4x + b
(where b is the y intercept)
to find b, plug in point A and you'll get:
2 = -1/4(16) + b
2 = -4 + b
6 = b
the equation will be:
y = -1/4x + 6
Answer:
12.5%
Step-by-step explanation:
8 / 64*100 =
(8 * 100) / 64 =
800 / 64 = 12.5
Hope this helped buddy! :D
