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3 years ago

The dot plots below show the weights of the players of two teams:

Mathematics

2 answers:

Inessa [10]3 years ago

8 0

C) Both groups are similar

Nadusha1986 [10]3 years ago

3 0

Answer:B

Step-by-step explanation:

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Total profit P is defined as total revenue R -= total cost C, and is given by the function Upper P left parenthesis x right par

Goshia [24]

Answer:

Step-by-step explanation:

P(x) = R(x) - C(x)

Where,

P(x) = Total profit

R(x) = Total revenue

C(x) = Total cost

R(x)equals150.97 x minus 0.3 x squared

R(x) = 150.97x - 0.3x^2

Upper C left parenthesis x right parenthesis equals 4529.10 plus 0.5 x squared.

C(x) = 4529.10 + 0.5x^2

P(x) = R(x) - C(x)

= (150.97x - 0.3x^2) - ( 4529.10 + 0.5x^2)

= 150.97x - 0.3x^2 - 4529.10 - 0.5x^2

= 150.97x - 0.8x^2 - 4529.10

P(x) = -0.8x^2 + 150.97x - 4529.10

4 0

3 years ago

In a shortage caused by a hurricane gas prices rose 15% it is now $2.80/gallon what was the price before

mash [69]

2.80*.15=.42

2.80-.42= 2.38

the answer is $2.38 (this was the price before)

8 0

3 years ago

Y=4.5 when x=3 find the variation of k

torisob [31]

The variation of K is what is found in front of X

5 0

3 years ago

Three planes intersect in Select one: O a. a plane O b. a point O c. a line segment

Arada [10]

Answer:

a line segment ✓....,.........

5 0

2 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago