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gladu [14]
3 years ago
9

$58 ski lift ticket;20% discount

Mathematics
2 answers:
lidiya [134]3 years ago
6 0
$11.6 would be 20% so the mark downed price would be 46.4
user100 [1]3 years ago
3 0
First you want to find how much 20% of $58 is. You do this by multiplying 58 by .2 which equals 11.6. Then, since it's a discount, you'll subtract 11.6 from 58 which equals 46.4. So the total cost of the ticket including the discount is $46.40.
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A gymnast has to hang from a ring that has a radius of 8 inches. what is the rings diameter?
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If it is 1:10 in virginia right now and its 6:10 in england how many hours are they apart
dalvyx [7]

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Step-by-step explanation:

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3 years ago
How are conditional probability and independent events related?
artcher [175]

Answer:

1. P(A|B) - option 2

2. does not affect - option 2

3. P(A) - option 1

Step-by-step explanation:

By the definition, the notation P(A|B) reads the probability of event A given that event B has occured. So, for the first gap correct choice is 2 - P(A|B).

If events A and B are independent, then the probability of event B occuring does not affect the probability of event A occuring. So, for the second gap correct choice is 2 - does not affect.

Events A and B are independent, then

P(A\cap B)=P(A)\cdot P(B)

Use formula for the conditional probability:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Since events A and B are independent, we get

P(A|B)=\dfrac{P(A)\cdot P(B)}{P(B)}=P(A)

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8 0
4 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
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