Answer:
Option C.) B
Step-by-step explanation:
we have
y > -2x+10 -----> inequality A
The solution of the inequality A is the shaded area above the dashed line y=-2x+10
The slope of the dashed line is negative m=-2
The y-intercept of the dashed line is (0,10)
The x-intercept of the dashed line is (5,0)
y > (1/2)x-2 -----> inequality B
The solution of the inequality B is the shaded area above the dashed line
y= (1/2)x-2
The slope of the dashed line is positive m=1/2
The y-intercept of the dashed line is (0,-2)
The x-intercept of the dashed line is (4,0)
using a graphing tool
The solution of the system of inequalities is the shaded area
see the attached figure
Points B and I are solution to the system of inequalities
Answer:
see explanation
Step-by-step explanation:
Point A is the Incentre of the triangle
This is the point where the 3 angle bisectors intersect
The incentre is equally far away from the triangle's 3 sides , then
AM = AL = 6
Area = Length x width.
30 = w x 3w +1
Simplify:
3w^2 + w = 30
Subtract 30 from both sides:
3w^2 + w -30 =0
Factor
(w-3)(3w+10) = 0
Solve for the w's:
w = 3 and x = -3 1/3
Since the number cant be negative w = 3
The width = 3 cm.
The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
Read more about linear programming at:
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Using the formula y=mx+b, you can simplify the equation to y=-4.5x+28 which means that the slope (m) equals -4.5 and the y-intercept (b) equals 28.