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Tamiku [17]
3 years ago
6

Ing Up Angles

Mathematics
2 answers:
natima [27]3 years ago
7 0

Answer:

180° is the correct answer. Hope this helped :)

Step-by-step explanation:

irga5000 [103]3 years ago
6 0

Answer:

180°

Step-by-step explanation:

a convex polygon has n sides, then its interior angle sum is

S = ( n −2) × 180°

S=(3-2)*180°=180°

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A pair of corresponding side of two similar pentagons have length of 12cm and 28cm
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The ratio of their areas = 12^2 / 28^2
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Can someone please answer this question please answer it correctly and please show work please help me I need it
WARRIOR [948]

Answer:

-16.5 is the amount of distance he jumped and went down

Step-by-step explanation:

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3 years ago
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A student is given the rectangle and square shown. The student affirms that the two figures have the same perimeter. Is the stud
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3 years ago
Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.
nignag [31]

Answer:

we need to prove : for every integer n>1, the number n^{5}-n is a multiple of 5.

1) check divisibility for n=1, f(1)=(1)^{5}-1=0  (divisible)

2) Assume that f(k) is divisible by 5, f(k)=(k)^{5}-k

3) Induction,

f(k+1)=(k+1)^{5}-(k+1)

=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1

=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k

Now, f(k+1)-f(k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k

f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k

Take out the common factor,

f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)      (divisible by 5)

add both the sides by f(k)

f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)

We have proved that difference between f(k+1) and f(k) is divisible by 5.

so, our assumption in step 2 is correct.

Since f(k) is divisible by 5, then f(k+1) must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number n^{5}-n is a multiple of 5.

3 0
3 years ago
Find two positive real numbers whose product is a maximum. the sum is 80
Eduardwww [97]
Let's say the numbers are "a" and "b"

thus \bf y=ab\qquad 
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a+b=80\\
b=80-a
\end{cases}\implies y=a(80-a)\implies y=80a-a^2\\\\
-----------------------------\\\\
\cfrac{dy}{da}=80-2a

set the derivative to 0, and check the critical points, there's only one anyway

and do a first-derivative test, to see if it's a maximum
4 0
3 years ago
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