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3 years ago

Find the missing term in each pair of equivalent ratios ____:13=48:104

1 answer:

7 0

You can treat ratios as fractions
x:13=48:104
x/13=48/104
simplify 48/104
48/104=24/52=12/26=6/13
x/13=6/13
multiply both sides by 13
x=6

the missing number is 6

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Which of the following options results in a graph that shows exponential growth? f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x

Leto [7]

It's important that you use the correct symbol to indicate exponentiation.

<span>f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x f(x) = 0.9(5)−x should be written as:

</span><span>f(x) = 0.4(3)^x f(x) = 3(0.5)^x f(x) = 0.8(0.9)^x f(x) = 0.9(5)−x.

Please double-check that last problem, as I am unsure of whether you meant 0.9^5 or (0.9)(5).

f(x) = 0.4(3)^x is definitely an exponential function.

Please try again. Do those problems that you can do an ask questions about the others.

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3 years ago

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Step-by-step explanation:

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3 years ago

Which of the following lists of fractions are in order from least to greatest? Select TWO that apply.

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3 years ago

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel

serious [3.7K]

Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.

Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is $|S| = C(40,6)$ .

Let E be the event of selecting none of the correct six integers.

The total number of ways to select the 6 incorrect numbers from 34 numbers is:

$|E| = C(34,6)$

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is

$P(E) = \frac{|E|}{|S|}$

$= \frac{C(34, 6)}{C(40, 6)}\\\\= \frac{1344904}{3838380}\\\\=0.35$

Therefore, the probability is 0.35

Check the attached files for additionals

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3 years ago