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Sholpan [36]
2 years ago
12

What does OH= and PK=

Mathematics
1 answer:
trapecia [35]2 years ago
4 0

The measure of OH and PK are 10 and 8 respectively

<h3>Circle theorems</h3>

These are theorem used to solve for the angles in a circle. From the given diagram, the triangle OHK projects from the chord HK

This makes the triangle an isosceles triangle and since two of their sides are equal, hence OH = OK

Given that OK = 10, hence the measure of OH is 10

Similarly the measure of HP and PK are also equal

Learn more on circle theorem here: brainly.com/question/6240879

#SPJ1

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Triangle F G E is shown. Angle F E G is a right angle. The length of hypotenuse F G is 18.6 inches and the length of F E is 12 i
Delicious77 [7]

Answer:

Measure of ∠FGE is 40.2°.

Step-by-step explanation:

Refer to the attachment.

Consider ΔFGE. Given that ∠FEG = 90° and ∠FGE is x°.

To find the value of ∠FGE use trigonometric ratios.

Use sine ratio to find the value of ∠FGE.

\sin \theta=\dfrac{opposite\:side}{hypotenuse\:side}

Rewriting it in terms of x° as follows,

\sin x=\dfrac{opposite\:side}{hypotenuse\:side}

Now find the opposite and hypotenuse side of the angle ∠FGE.

So opposite side of ∠FGE is FE and hypotenuse side of ∠FGE is FG.

Substituting the values,

\sin x=\dfrac{FE}{FG}

Given that length of FE is 12 inch and FG is 18.6 inch.

Substituting the value,

\sin x=\dfrac{12}{18.6}

To find the value of x, taking inverse sin.

x=\arcsin \left(\dfrac{12}{18.6}\right)

Calculating the value,

x=40.17

Rounding to nearest tenth the value of angle is 40.2

Therefore measure of ∠FGE is 40.2° .

8 0
3 years ago
The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
mihalych1998 [28]

Answer:

We conclude that the mean number of calls per salesperson per week is more than 37.

Step-by-step explanation:

We are given that the Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales representatives make an average of 37 sales calls per week on professors.

To investigate, a random sample of 41 sales representatives reveals that the mean number of calls made last week was 40. The standard deviation of the sample is 5.6 calls.

<em><u>Let </u></em>\mu<em><u> = true mean number of calls per salesperson per week.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq 37   {means that the mean number of calls per salesperson per week is less than or equal to 37}

<u>Alternate Hypothesis,</u> H_A : \mu > 37   {means that the mean number of calls per salesperson per week is more than 37}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of calls made last week = 40

             s = sample standard deviation = 5.6 calls

             n = sample of sale representatives = 41

So, <em><u>test statistics</u></em>  =   \frac{40-37}{\frac{5.6}{\sqrt{41} } }  ~ t_4_0

                               =  3.43

Hence, the value of test statistics is 3.43.

<em>Now at 0.025 significance level, the t table gives critical value of 2.021 at 40 degree of freedom for right-tailed test. Since our test statistics is more than the critical value of t as 3.43 > 2.021, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the mean number of calls per salesperson per week is more than 37.

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Each line has a difference of four

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Graph this, using a dashed curve (not a solid curve).  Then shade the coordinate plane ABOVE the graph.
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What is the rate of change?<br> the second 1 and second 4?
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Idek but I do know that 12x8= 72
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