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4 years ago

How are cells similar to a factory or a business? List five similarities

2 answers:

8 0

I have 5
1. the work together
2. they produce things
3. they help something or someone
4. they send things to locations
5. packaging department

4vir4ik [10]4 years ago

6 0

Answer:

1. the work together

2. they produce things

3. they help something or someone

4. they send things to locations

5. packaging department

Explanation:

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Should companies be able to own the DNA conatined in plant seeds?

Paha777 [63]

Yes i think so :) hope this helped

3 0

3 years ago

4.305 liters to microliters

Hatshy [7]

4.305 L = 4.305 × 10^6 µL

1 µL = 10^(-6) L

∴ 4.305 L × [1 µL/10^(-6) L] = 4.305 × 10^6 µL

6 0

3 years ago

Why is phenolphthalein not a good indicator to use for a titration that has a ph of 6.0 at the equivalence point?

vekshin1

Phenolphthalein is not a good indicator to use for a titration for a solution that has a ph of 6.0 at the equivalence point because the color change of the solution at this pH level is not sharp. It changes the color of the solution to pink starting from pH 8.3 to 10. A pH level lower than 8.3 would only show a colorless solution. Thus, you would not be able to distinguish whether the solution has reached its equivalence point at pH 6.0. It is best to use this indicator for a system that is using a strong base titrated with a weak acid.

5 0

3 years ago

Lorico [155]

Answer:

Phosphorus

Explanation:

Group V elements- Nitrogen, Phosphorous

period 3- Sodium, Magnesium, Aluminium, Silicon , Phosphorous, Sulphur, Chlorine and Argon

Group v and period 3 is phosphorus

6 0

3 years ago

How many grams of krypton gas will occupy 2.55 liters at 1.25 atm if it occupies 3.75 liters at 0.750 atm at 255 K

tatiyna

Answer:

There will be 94.7 grams of krypton gas

Explanation:

Step 1: Data given

at 255K and 0.750 atm the volume is 3.75 L

At 1.25 atm the volume is 2.55 L

Molar mass of krypton = 83.798 g/mol

Step 2: Calculate number of moles

p*V = n*R*T

with p = the pressure of the krypton gas = 0.750 atm

with V = the volume of the krypton gas = 3.75 L

with n = the number of moles = TO BE DETERMINED

with R = the gasconstant = 0.08206 L*atm/ mol * K

with T = the temperature = 255 K

n = R*T / p*V

n = (0.08206 * 255)/ (0.750 * 3.75)

n = 0.744 moles

Step 3: Calculate new number of moles

P1*V1 = P2*V2

P1*V1 = n1*R*T

P2*V2 = n2*R*T

(P1*V1)/R*T = (P2*V2)/n2*R*T

Since R and T do not change we can write as followed:

(P1*V1) = (P2*V2) /n2

n2 = (P2*V2) / (P1*V1)

n2 = (2.55 *1.25)/(0.75*3.75)

n2 = 1.13 moles

Step 4: Calculate mass of krypton gas

mass = Number of moles * Molar mass

mass of krypton gas = 1.13 moles * 83.798 g/mol = 94.69 grams ≈ 94.7 grams

There will be 94.7 grams of krypton gas

5 0

3 years ago