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3 years ago

Geometry Proving Triangles Congruent Maze . Plz help

Mathematics

1 answer:

Olenka [21]3 years ago

4 0

Answer:

Step-by-step explanation:

up SAS; Right ASA; upSSS;

up not possible to prove; left ASA; down SAS

left SSS; up ASA; end

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Find the quotient 16)4.88

kap26 [50]

Answer:

if this is 4.88/16 then the answer is 0.305.

7 0

3 years ago

In February, Alec had 1,571 visitors to his website. In March, he had 1,380 visitors to his website. What is the percentage decr

Yakvenalex [24]

A. 12.2%

Steps:
1) 1380-1571= -191
2) -191/1571= -0.12
3) -0.12(100) = 12.15 = 12.2%

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4 years ago

Find the perimeter AND area of the parallelogram ABCD. Show all work

nexus9112 [7]

Since, this is parallelogram

so, opposite sides are equal

We will find value of sides

Calculation of AB:

we are given point A=(-2,3)

point B=(4,0)

we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AB=\sqrt{(4+2)^2+(3-0)^2}$

$AB=3\sqrt{5}$

Since, this is parallelogram

so, opposite sides are equal

so,

$CD=AB=3\sqrt{5}$

Calculation of AD:

point A =(-2,3)

point D=(-5,2)

we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AD=\sqrt{(-5+2)^2+(2-3)^2}$

$AD=\sqrt{10}$

Since, this is parallelogram

so, opposite sides are equal

so,

$BC=AD=\sqrt{10}$

Calculation of AE:

point A=(-2,3)

point E=(-3,1)

we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AE=\sqrt{(-3+2)^2+(1-3)^2}$

$AE=\sqrt{5}$

(a)

we know that

perimeter of a parallelogram is sum of all sides

so,

perimeter is

$=AB+BC+CD+DA$

now, we can plug values

$=3\sqrt{5}+\sqrt{10}+3\sqrt{5}+\sqrt{10}$

$=6\sqrt{5}+2\sqrt{10}$ ...........Answer

(b)

we can use area of parallelogram formula

$A=AE\times CD$

we can plug values

$A=\sqrt{5}\times 3\sqrt{5}$

$A=15$ ............Answer

4 0

3 years ago

Do anyone know how to do this?

kykrilka [37]

Answer:

1.) x=4

2.) x=14

Step-by-step explanation:

FOR #1:

1.) In order to solve the parallelogram, you must know that each opposite sides must equal...

so KL=JM and KJ=LM

2.) To solve for "x", you must substitute

$KL= 7x-2\\JM=12x-22$

so it should end up with...

$7x-2=12x-22$

3.) Solve the equation with some algebra

$7x-2=12x-22\\-5x=-20\\x=4$

FOR #2:

1.) In order for a square, rectangle, parallelogram, (or any shape with four sides), it must equal to 360°. And you just have two given angles, which equal to 180, so that means the unknown equals to 180...So in this case you should have

$(3x+5)+(9x-17)+180=360$

as your equation...

2.) Solve with algebra

$(3x+5)+(9x-17)+180=360$

$3x+5+9x-17=180\\12x-12=180\\(\frac{1}{12}) 12x=168 (\frac{1}{12})\\x=14$

<u><em>multiplied</em></u>

3 0

3 years ago

Read 2 more answers

Let n = 60! + 55! + 50! the unit digit of n and a number of digits to the left of the units digits are consecutive zeros before

Archy [21]

n=8320987125437793528348710310901843271933297732006335848276356027645952000000000000

So you can see there are 12 zeros before you hit the first non-zero, which is 2.

8 0

3 years ago