The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2 units up to form polygon A′B′C′D′. Match each vertex of polygon A′B′C′D′ to its coordinates.Tiles
(2, 1)A′(2, -1)
(1, 1)B′<span>(-3, 4)</span>
(3, 0)C′(2, -1)
(2, 3)D′(-2, 5)

8 0

3 years ago

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Determinar la longitud de la hipotenusa del siguiente triángulo si se conocen las medidas que se indican de los demás triángulos

Zina [86]

it helps a lot in math us it won't let me do it

3 0

3 years ago

Help me on this please

Butoxors [25]

Answer:

y=35x+50

35*8=280

280+50=330

yes there will be 10 dollars left

I hope this is good enough:

8 0

3 years ago

Trigonometry

Natasha_Volkova [10]

Answer:

Step-by-step explanation:

For a triangle the area is

$A=\frac{1}{2}bh$

If our triangle is isosceles and the 2 congruent sides each measure 4 and they include an angle of 40 degrees, let's say that the vertex angle is 40 and the sides that are not the base each measure 4. If we drop an altitude from the vertex to the base, we cut the triangle into 2 right triangles, with the vertex angle being 20 degrees and the hypotenuse being 4. To find the base, then, which is opposite the angle, we use the sin ratio:

$sin(20)=\frac{b}{4}$ and

4sin(20) = b so

b = 1.368

But we need the whole base, and that is only half of it. So

2b = 2.736

To find the height, which is adjacent to the angle, we use the cos ratio:

$cos(20)=\frac{h}{4}$ and

4cos(20) = h so

h = 3.759

Now we have enough info to find the area of the triangle using the triangle area formula from above:

$A=\frac{1}{2}(2.736)(3.759)$ and

A = 5 meters squared.

7 0

3 years ago