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MrRissso [65]
3 years ago
15

Help...

Mathematics
1 answer:
GaryK [48]3 years ago
5 0
What are you asking cause I do not get it
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A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1690 feet, what are the dimensions o
lawyer [7]

Answer:

The width of the field is 65 feet.

The length of the field is 780 feet.

6 0
4 years ago
A map of an airport is laid out in a coordinate plane. An aeroplane starts at a gate at (0, 0.1). To reach a runway, the plane t
I am Lyosha [343]

Take the numbers and divide them i believe

4 0
3 years ago
Read 2 more answers
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
(16+5) + blank = 16 + (5+10)
Murrr4er [49]

Answer:

Im not sure, but I think its like this...

Step-by-step explanation:

(16+5) + 10 = 16 + (5+10)

I hope this is correct!!

3 0
3 years ago
HELP! WILL NAME BRAINEST!!!!
Irina18 [472]

the best answer is b

5 0
3 years ago
Read 2 more answers
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