<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x
<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)
Since both the distance they traveled are the same, we equate the distance to solve for x.
<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60
<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph
Answer: The spend of the two trains are 60 mph and 108 mph.
2x + 5y = 270
Two times the amount of wheeled backpacks. Let x = wheeled backpacks.
Five times the amount of non wheeled backpacks. Let y = non wheeled backpacks.
Total backpacks will be 330 so 330 - 60 = 270
Therefore you get 2x + 5y = 270
<span>What is the value of c?
5x2 - 3y2 - 20x + 6y + 2 = 0
Select one:
a. 2
b. 4
c. √4
d. √8
This was an older question and someone said the answer was D and I got it right.</span>
(Y1-Y2)/(X1-X2)
(2-4)/(-2-3)
-2/-5
2/5
The probability is (0.10 * 0.50 + 0.01 * 0.20 + 0.89 * 0.01) * 100% = 6.09%.
