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mr Goodwill [35]
3 years ago
9

PLEASE SOMEONE DO THIS IM RUSHING SO BAD AND IM CRYING - GIVING BRAINLIEST!!!!!

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

1.) $1.07

2.) $2.25

3.) $14.20

Step-by-step explanation:

1.) Toonie = 2 CAD

CAD = USD $1.57

$1.57 - $0.50 = $1.07 (USD)

2.) $2.75 - $5 = $2.25 (USD)

3.) $20 x 4 = 80

$80 - $65.80 = $14.20 (USD)

Hope this helped!

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frutty [35]
68% because it’s between them
5 0
2 years ago
4.8 + 2.2w − 1.4w + 2.4
Lostsunrise [7]

Answer:

7.2 + 0.8w

Step-by-step explanation:

combine like terms. Like terms have same variable with same power.

2.2w and (-1.4w) are like terms & 4.8 and 2.4 are like terms.

4.8 + 2.2w - 1.4w + 2.4 = 4.8 + 2.4 + 2.2w - 1.4w

                                      = 7.2 + 0.8w

5 0
2 years ago
Read 2 more answers
How to divide 83.7 by 0.03
Mandarinka [93]
The answer would be 2790
6 0
3 years ago
A museum has a 1/2 ounce piece of a precious metal. When the museum first received the piece, it had a value of $90. Its value h
Alex777 [14]
The current value of the precious metal is $144/oz

-First, you'd want to determine the original value per ounce since that's what the final unit being asked for is.

- Since the original value of the half ounce piece is given, this first step is fairly simple. You just double ninety.

- We now know that the metal was worth $180/oz when the museum first received it.

- We need to determine the current price of the metal now that is has had a twenty percent loss of value.

- My favorite way to factor in 20% is simply to divide by five since it's a lot more simple than finding the ratio of x$/1%

- $180/5=$36

- Thirty-six dollars is the price drop over the course of the museum possessing the precious metal.

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5 0
3 years ago
A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa
MariettaO [177]

Answer:

The maximum height of the second pluck is greater than that of the first pluck, hence the second pluck travels further  

Also the distance of the maximum height of first pluck from the player is less than the distance of the second pluck from the player hence the second pluck travels further

Step-by-step explanation:

From the question we are told that

  The maximum height of the first pluck is  h_1 =  3 \  ft

   The height of the second height is mathematically represented as

              $y=x\left(0.15-0.001x\right)

=>           y=0.15x -0.001x^2

Generally at maximum height  y' = 0

So

      y'=0.15 -0.002 x = 0

=>    x =  75 \  ft

Here 75 ft is the horizontal distance the second pluck traveled at maximum height

   So the maximum height of the second pluck is mathematically represented as

       y=0.15(75) -0.001(75)^2

=>     y=  5.625 \  ft  

So comparing the maximum height  of the first and the second pluck we see that the maximum height of the second pluck is greater than that of the first pluck, hence the second pluck travels father

3 0
3 years ago
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