Suppose bug B lands on the end of the wiper blade closest to the pivot. Assume the wiper turns through an angle of 120°. In one
cycle of the wiper blade, how far has the bug traveled? (Round your answer to two decimal places.)
1 answer:
Answer:
s = 8*π in
Step-by-step explanation:
Given:
- The complete data is given in the figure (attached):
Solution:
- The bugs lands on the end of the wiper blade closest to the pivot. The arc length (s) swept by a wiper in one cycle i.e θ = 120° would be given by:
s = 2*r*θ
- Where, r: The distance between the bug and the pivot = 6 in
θ : Angle swept in radians
- The distance travelled by the bug is s:
s = 2*(6)*( 120 / 180 ) * π
s = 8*π in
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Hello!
You can only add variables with the same base and exponent
8u^3 + 4u^3 = 12u^3
8u^2 + 0 = 8u^2
0 + -6u = -6u
6 + 3 = 9
Put the sums together
12u^3 + 8u^2 - 6u + 9
The answer is
Hope this helps!
You can only add variables with the same base and exponent
8u^3 + 4u^3 = 12u^3
8u^2 + 0 = 8u^2
0 + -6u = -6u
6 + 3 = 9
Put the sums together
12u^3 + 8u^2 - 6u + 9
The answer is
Hope this helps!
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A population p of migrating butterflies changes over time it is represented by the equation
Where w is number of weeks.
To find,
The population after 2 weeks.
Solution,
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