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Dominik [7]
3 years ago
5

Explain each step in the process of finding the area of a circle given the circumference.

Mathematics
2 answers:
Mama L [17]3 years ago
5 0

Answer:

plug in your numbers and solve

Step-by-step explanation

sergeinik [125]3 years ago
5 0

Answer:

Sample Response: Substitute the known circumference into the formula C = πd. Divide by π to find the diameter. Then divide the diameter in half to find the radius. Substitute the radius into the area formula, A = πr2. Square the radius and multiply by π to get the area.

Step-by-step explanation:

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LOTS OF POINTS hard math though
Zinaida [17]
False because x is -5
4 0
2 years ago
Can someone check if this is right please? If not what is the correct way?
Charra [1.4K]

A, B, and C are the coefficients. They are not the terms as you have written now.

A quadratic equation is in the form Ax^2 + Bx + C. Therefore, A = 1, B = 8, and C = -6.

The axis of symmetry is  found using the equation -b/2a, as you've done. Therefore, the axis of symmetry is -8/2(1) = -4.

Hope this helps!! :)

6 0
3 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
2 years ago
Read 2 more answers
What are one dimensional figures
agasfer [191]
Hello!

In geometry there are three dimensions.

Something that is one dimensional is neither flat, wide, or tall. It is just a line.
——————————————
Something two dimensional is flat and wide but has no height. An example of this is a square.

Something three dimensional is wide and tall, and has flat faces. An example is a cube.

To answer your question something one dimensional is something that is not flat, wide, or tall, such as a line.

Hope this helped!
3 0
3 years ago
How do I solve this question (19a)?
fredd [130]
Answer i think would be
l-4x+4l
---------
x-1
8 0
3 years ago
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