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-Dominant- [34]
3 years ago
7

Help a girl out ? i linked the attachment .Thank you smmm have a great day.

Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0

Answer:

The expression that equivalent to  \frac{12x^{4}}{4x^{16}}  is 3x^{4-16} ⇒ C

Step-by-step explanation:

Let us revise some rule of exponents

  • a^{m} × a^{n} = a^{m+n}
  • \frac{a^{m}}{a^{n}} =  a^{m-n}
  • (a^{m})^{n} = a^{mn}

Let us solve the question

∵ The expression is \frac{12x^{4}}{4x^{16}}

→ Simplify the fraction 12/4 first

∵ 12/4 = 3

∴  \frac{12x^{4}}{4x^{16}} = 3 ( \frac{x^{4}}{x^{16}})

→ By using the second rule above to simplify the variable

∵  \frac{x^{4}}{x^{16}} = x^{4-16}

∴  \frac{12x^{4}}{4x^{16}} = 3x^{4-16}

∴ The expression that equivalent to  \frac{12x^{4}}{4x^{16}}  is 3x^{4-16}

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A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining th
Anuta_ua [19.1K]
These are two questions and two answers:

Question 1:

<span>A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work.

Answer: </span><span>The negative value of the radicand means that the equation does not have real solutions.

Explanation:

1) With radicand the statement means the disciminant of the quadratic function.

2) The discriminant is: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation: ax² + bx + c

3) Then, for 3x² - 15x + 20, a = 3, b = - 15, and c = 20

and the discriminant (radicand) is: (-15)² - 4(3)(20) = 225 - 240 = - 15.

4) The negative value of the radicand means that the equation does not have real solutions.

Question 2:

Part B: Solve 3x^2 + 5x − 8 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Answer:
</span> two solutions x = 1 and x = - 8/3x

Explanation:

1) I choose factoring (you may use the quadratic formula if you prefer)

2) Factoring

Given: 3x² + 5x − 8 = 0

Make 5x = 8x - 3x: 3x² + 8x - 3x - 8 = 0

Group: (3x² - 3x) + (8x - 8) = 0

Common factors for each group: 3x(x -1) + 8(x - 1) = 0

Coomon factor x - 1: (x - 1) (3x + 8) = 0

The two solutions are for each factor equal to zero:

x - 1 = 0 ⇒ x = 1
3x + 8 = 0 ⇒ x = -8/3

Those are the two solutions. x = 1 and x = - 8/3
4 0
3 years ago
Help please really don’t know what the answers is
Arturiano [62]

Answer:

No

Step-by-step explanation:

The Side-Angle-Side rule of congruence

two triangles are congruent if two sides and one included angle in a given triangle are equal to the corresponding two sides and one included angle in another triangle.

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAPP !!​
Andreas93 [3]

Answer:

1. you start with $ 3 and save $1 each month

2. your total savings is 3 times the number of month multiplied by itself

3. you save $3 the first month and then each month the amount triples

Step-by-step explanation:

1.

as y axis represents savings while x axis represents months

the statement "you start with $ 3 and save $1 each month"

is best described by the graph of straight line having slope of 1 and intercept of 3.

2. your total savings is 3 times the number of month multiplied by itself

          = 3(x)(x)

          = 3x^2

3.  as y axis represents savings while x axis represents months

the statement  "you save $3 the first month and then each month the amount triples" is best described by the exponential graph starting to rise from point (1,3) which means $3 save at 1 month.

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4 0
3 years ago
What is the probability of pulling a heart
maw [93]

Answer: The probability of drawing a heart out of the deck is 13/52, or 1/4. The probability of drawing an even number as card #2 (c∈{2,4,6,8,10}) for any suit is 20/51, except when the first card drawn is an even heart, then the probability of the second draw is 19/51.

Step-by-step explanation:

3 0
3 years ago
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A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

  $E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
3 years ago
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