1.<span>
The midpoint </span>MPQ of PQ is given by (a + c /
2, b + d / 2)<span>
2.
Let the x coordinates of the vertices of P_1 be :
x1, x2, x3,…x33
the x coordinates of P_2 be :
</span>z1, x2, x3,…z33<span>
and the x coordinates of P_3 be:
w1, w2, w3,…w33</span>
<span>
3.
We are given with:
</span>
X1
+ x2 + x3… + x33 = 99
We also want to find the value of w1 + w2 + w3… + w33.<span>
4.
Now, based from the midpoint formula:</span>
Z1 = (x1 + x2) / 2
Z2 = (x2 + x3) / 2
Z3 = (x3 + x4) / 2
Z33 = (x33 + x1) / 2<span>
and
</span>
<span>W1
= (z1 + z1) / 2
W2 = (z2 + z3) / 2</span>
<span>W3
= (z3 + z4) / 2
W13 = (z33 + z1) / 2
.
.
5.</span>
<span>W1
+ w1 + w3… + w33 = (z1 + z1) / 2 + (z2 +
z3) / 2 + (z33 + z1) / 2 = 2 (z1 + z2 + z3… + z33) / 2</span>
<span>Z1
+ z1 + z3… + z33 = (x1 + x2) / 2 + (x2 + x3) / 2
+ (x33 + x1) / 2
</span>2 (x1 + x2 + x3… + x33) / 2 = (x1 + x2 +
x3… + x33 = 99<span>
<span>Answer: 99</span></span>
Answer:
Therefore 'x' is equal to 65.4°
Step-by-step explanation:
In Right Angle Triangle ABC
∠ B = 90°
AC = Hypotenuse = 12
CB = Adjacent Side = 5
To Find:
∠ C = x
Solution:
In Right Angle Triangle ABC Cosine Identity we have
Substituting the values we get
Therefore 'x' is equal to 65.4°
If i knew the answer i would help buttt i don’t lol.
Answer:
Step-by-step explanation:
First, you should put the axis of symetry as 5, -7 because f(x)= (x-h)^2+k and h is 5 and k is -7. the axis of symetry is x=5 because that is the "folding point" of the graph. Next, you would have to plug In 4 and 6 as your helping points to tell you where the other points of the function are going to be.
Plug 4 in and you get -6. plug 6 in and you get -6. plot the points (4, -6) and (6,-6).
Hope this helps!
:)
$323 dollars just minus them and then you have your answer .
