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Romashka [77]
3 years ago
14

When rolling a fair number cube with numbers 1 through 6, what is the probability of

Mathematics
2 answers:
lakkis [162]3 years ago
8 0
The probability of rolling a number less than 3 is B: 1/3
Gnom [1K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

The total number of faces on a cube is 6.

The numbers under 3 are 1 and 2.

So numbers 1 and 2 give success.

P(<3) = 2/6

P(<3) = 1/3

The answer is B.

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What is 5 to the power of 8 over 5 to the power of 3 multiplied by 4
klio [65]

Answer:

12500

Step-by-step explanation:

im just in middle school but if I did this correctly then it should be 12500.

first set up your equation

then do your exponents

then divide your nomonator by your denomonator

then multiply that number by 4

6 0
3 years ago
Read 2 more answers
Which of the following sets could be the sides of a right triangle?
o-na [289]

Answer:

1st answer

Step-by-step explanation:

From pythagorus theorem.

Since hypotenuse

=  \sqrt{  {2}^{2}  +  {3}^{2}  }=   \sqrt{ {13}}

4 0
3 years ago
How to reduce 10/4 i don’t know how to
vredina [299]

answer: 10/4 reduced is 2.5/1 or 2.5.

work: what we are doing is trying to divide ten into groups of four. how many times does 10 fit into four? well, look at the multiples of four, 4, 8, 12... we can see that 8 fits into ten, but 12 doesn't. that means two whole fours can fit into ten (since 4 x 2 = 8) so we still have a  2 left over from the ten. since 2 is one half of four, we can fit in another .5. so, ten can be fit into 2.5 groups. hope this helps, have a great day!


3 0
3 years ago
Read 2 more answers
The difference of two numbers is 3 and their quotinet is 2 what are the 2 numbers
blsea [12.9K]
The two numbers are 6 and 3
3 0
3 years ago
A membership committee of three is formed from four eligible members. let the eligible members be represented by a, b, c, and d.
Lynna [10]

The correct statements are:

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1)

There are four ways to choose the committee.

This statement is true.

since we have to choose 3 members out of the 4 members so we can use the method of combination.

2)

There are three ways to form the committee if person D must be on it.

This statement is also true.

since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3)

If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

i.e. there are 35 combinations possible.

4)

If persons B and C must be on the committee, there are two ways to form the committee.

if B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5)

If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be in the committee then as in last option we have to choose any one of the two person left.

so possible number of ways are 2.

Hence, the statement is false.

Learn more about Combinations:

brainly.com/question/4658834

#SPJ4

3 0
3 years ago
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