All categories

3 years ago

Solve the equation on the interval [0,2pi) 4sin^2x-3=0

Mathematics

1 answer:

bagirrra123 [75]3 years ago

4 0

4sin²x-3=0
4sin²x=3
sin²x=3/4
sinx=√3/2 or -√3/2
x=π/3, 2π/3, 4π/3, or 5π/3

You might be interested in

N+4-9 - 5n when simplifying

natita [175]

Answer:

-4n - 5

Step-by-step explanation:

4 - 9

= -5

-5n + n

Combine like terms

= -4n

-4n - 5

7 0

3 years ago

10 POINTS!

AURORKA [14]

The triangular prism has 5 faces; two triangle faces and three rectangular faces.

We can find the area of one of the triangle faces by doing ((base * height) / 2). In this case, it would be ((2 * 2) / 2), which of course would equal 2"². Multiplied by two for the two triangles, which would be 4.

To find the area of one of the rectangles, we do (length * base), which would be (5 * 2) in our case, giving us 10. Multiply by 3 for the 3 faces, and we got 30"².

30 + 4 = 34"²

4 0

3 years ago

Read 2 more answers

(1/4)^3z-1 =16^z+2*64^z-2<br><br> Z=___<br><br> Please help

wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

$(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274$

Hence, the value of Z = 0.198877274

8 0

3 years ago

Read 2 more answers

Please help , will mark brainliest.

bagirrra123 [75]

Answer: 30 ft

hope this helped :)

4 0

3 years ago

A cylinder has a 12-inch diameter and is 15 inches tall. It is filled to the top with water. A 6-inch-diameter ball is placed wi

Tems11 [23]

The volume of the cylinder is the space occupied by the cylinder. The volume of the water in the cylinder is 1583.36266 in³.

<h3>What is the volume of a cylinder?</h3>

The volume of the cylinder is the space occupied by the cylinder. It is calculated with the help of the formula,

$\text{Volume of the cyllinder}= \pi r^2h$

As it is given that the diameter of the cylinder is 12 inches while the height of the cylinder is 15 inches, also, it has a ball of the diameter of 6 inches placed inside the cylinder, therefore, the volume of the water that is inside the cylinder is the difference in the volume of the cylinder and the volume of the spherical ball.

$\text{Volume of the cyllinder}= \pi r^2h = \dfrac{\pi}{4}d^2 h$

Substitute the values,

$\begin{aligned}\text{Volume of the cyllinder}&= \dfrac{\pi}{4}d^2 h\\& = \dfrac{\pi}{4} \times (12^2) \times 15\\ &=1696.46\rm\ in^3\end{aligned}$

Now, the volume of the ball is equal to the volume of the sphere therefore, the volume of the ball can be written as,

$\text{Volume of the sphere} = \dfrac{4}{3}\pi r^3$

$= \dfrac{4}{3}\pi r^3\\\\= \dfrac{4}{3}\times \pi \times (3^3)\\\\= 113.097\rm\ in^3$

Further, the volume of the water that is inside the cylinder can be written as,

The volume of water = Volume of the cylinder - Volume of the sphere

= 1696.46 - 113.097

= 1583.36266 in³

Hence, the volume of the water in the cylinder is 1583.36266 in³.

Learn more about Volume of the Cylinder:

brainly.com/question/1780981

5 0

2 years ago