3 years ago

Solve the equation on the interval [0,2pi) 4sin^2x-3=0

Mathematics

1 answer:

bagirrra123 [75]3 years ago

4 0

4sin²x-3=0
4sin²x=3
sin²x=3/4
sinx=√3/2 or -√3/2
x=π/3, 2π/3, 4π/3, or 5π/3

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