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stiks02 [169]
3 years ago
8

Solve the equation on the interval [0,2pi) 4sin^2x-3=0

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0
4sin²x-3=0
4sin²x=3
sin²x=3/4
sinx=√3/2 or -√3/2
x=π/3, 2π/3, 4π/3, or 5π/3
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