Please help , will mark brainliest.

Dara ran on a treadmill that had a readout indicating the time remaining in her exercise session. When the readout indicated 24

Nat2105 [25]

Answer:

E. 16 min 12 sec

Step-by-step explanation:

Let x represent total time taken to complete the exercise.

We have been given that Dara ran on a treadmill that had a readout indicating the time remaining in her exercise session.

When the readout indicated 24 min 18 sec, she had completed 10% of her exercise session. This means that 90% time of exercise is equal to 24 minutes and 18 seconds.

18 seconds will be equal to 0.3 minutes.

Let us find total time of exercise as:

$\frac{90}{100}x=24.3$

$0.90x=24.3$

$\frac{0.90x}{0.90}=\frac{24.3}{0.90}$

$x=27$

To find readout when Dara had completed 40% of her exercise session, we need to find 60% of total time.

$\frac{60}{100}(27)=0.60(27)=16.2$

Since our time in in minutes, so we will convert 0.2 minutes to seconds by multiplying by 60.

$0.20(60)=12$

Therefore, the readout will indicate 16 minutes 12 seconds, when Dara had completed 40% of her exercise session.

8 0

3 years ago

PLEASE!!!!!!!!!! HELP NEEDED QUICK

Triss [41]

We have to find the expected value for the PlayBall lottery.
The price of the ticket = $1
Prize amount = $250
If a player wins, he will be winning $249 as the price is not paid back along with the prize amount. He is spending $1, getting back $250, so the net amount he is getting back is $249.

Now we have to find the probability of winning and losing.

Number of letters from A to T = 20
Number of digits from 0 to 9 = 10

Probability of picking up the same letter that was picked on that day = 1/20
Probability of picking up the same number that was picked on that day = 1/10

Thus, the Probability of picking up the same letter and same number that was picked on that day = $\frac{1}{20}* \frac{1}{10}= \frac{1}{200}$

Thus, the probability of winning = 1/200

The probability of losing = $1- \frac{1}{200}=\frac{199}{200}$

The expected value E for the PlayBall lottery will be:

$E= \frac{1}{200}(249)- \frac{199}{200}(1) \\ \\ 
E= \frac{1}{4} \\ \\ 
E=0.25$

Thus, the option C gives the correct answer

4 0

3 years ago

Given that S is the centroid of triangle MNO, find SQ.

AnnZ [28]

Answer:

|SQ|=5

Step-by-step explanation:

If S is the median, then OP is a median of triangle OMN.

This implies that:

|MP|=|NP|

$3x-4=x+4$

We group like terms and solve for x.

$3x-x=4+4$

$\implies 2x=8$

$\implies x=4$

Now we know that: MN:SQ=2:1

But MN=2x+2

This implies that:

2x+2:SQ=2:1

Put x=4

2(4)+2:SQ=2:1

10:SQ=2:1

Therefore |SQ|=5

7 0

3 years ago

Simplify the following: x^4 - 5x⁴ + x² - 6x²

lys-0071 [83]

Answer:

I think − 4 ⁴ − 5 ²

Step-by-step explanation:

I might be wrong.

3 0

2 years ago

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

brainly.com/question/24179531

#SPJ4

4 0

1 year ago