4 years ago

Please help!! final exam!! if x varies directly as y, and x=20 when y=4, find x when y=9

Mathematics

1 answer:

Dominik [7]4 years ago

7 0

Answer:

X=45

Step-by-step explanation:

Multiple y by 5

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HELP HELP HELP<br> HELP HELP <br> HELP <br> (STEP BY STEP)

Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

3 0

2 years ago

Need a Quick answer please

rusak2 [61]

Answer:

so i do not know that but hi

i just want points when i am bored

Step-by-step explanation:

3 0

3 years ago

What is the domain of the function y=in(x+2) x<-2 x>-2 x<2 x> x<-2 x>-2 x<2 x>2

aev [14]

For this case we must find the domain of the following function:

$y = ln (x + 2)$

By definition, the domain of a function is given by all the values for which the function is defined.

In this case, the argument of the expression must be greater than 0 to be defined.

$x + 2> 0\\x> -2$

Thus, the domain of the function is given by all the values of x greater than -2.

Answer:

Domain: $x> -2$

4 0

3 years ago

I guess u have to find the area

Nesterboy [21]

18
Because 6•3= 18
Hope this helped

7 0

3 years ago

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A customer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels,

VLD [36.1K]

He would use 9 bills, and 5 coins. (fours $10, one $5, four $1. three quarters, one dime, and one penny). I calculated it all to make sure the total came out as 49.86

8 0

4 years ago

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