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dezoksy [38]
3 years ago
9

explain how you can mentally determine whether 125 x 0.9 is less than, greater than, or equal to 125.

Mathematics
2 answers:
ra1l [238]3 years ago
6 0
It would be less then (<) because when u multiply by a number less then 1, it becomes smaller
Citrus2011 [14]3 years ago
3 0
Anything times 1 is equal to itself. Anything times less than one is less than itself. Anything times greater than one is greater than itself. Therefore, 125 times .9, which is less than one, is less than 125
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Tell me something you have wanted to say but never told anyone.
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6 0
2 years ago
What is a formula for the nth term of a given sequence
IceJOKER [234]

Answer:

a_n=-12-4(n-1)

Step-by-step explanation:

The given sequence is

-12,-16,-20...

The first term of this sequence is a_1=-12.

The common difference is

d=-16--12

d=-16+12=-4

The nth term of this arithmetic sequence is;

a_n=a_1+d(n-1)

We substitute the values for the first term and the common difference to obtain;

a_n=-12-4(n-1)

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4%20%5Cfrac%7B1%7D%7B9%7D%20%20%2B%201%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title="4 \
tino4ka555 [31]

Step-by-step explanation:

\tt{ 1. \:  \: 4 \frac{1}{9} + 1 \frac{1}{2}}

⇢ \tt{  \frac{37}{9}  +  \frac{3}{2} }

⇢ \tt{ \frac{37  \times 2 + 3 \times 9}{18} }

⇢ \tt{ \frac{74 + 27}{18} }

⇢ \tt{ \frac{101}{18}}

⇢ \boxed{ \tt{5 \frac{11}{18}} }

---------------------------------------------------------

\tt{ \: 2. \:  \: 4 \frac{1}{2} \div \frac{3}{5}}

⇢ \tt{ \frac{9}{2}  \times  \frac{5}{3}}

⇢ \tt{ \frac{9  \times 5}{2 \times 3}}

⇢ \tt{ \frac{45}{6}}

⇢ \boxed{ \tt{7 \frac{3}{6}} }

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
2 years ago
Evaluate x + 8 when x = 7<br><br> a. 15<br><br> b. 1<br><br> c. -1<br><br> d. 56
Tems11 [23]

Answer:

a) 15

Step-by-step explanation:

x+8

substitute x value in

7+8

=15

8 0
3 years ago
Read 2 more answers
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