The answers are as follows:
a) F(A, B, C) = A'B'C' + A'B'C + A'BC' + A'BC + AB'C' + AB'C + ABC' + ABC
= A'(B'C' + B'C + BC' + BC) + A((B'C' + B'C + BC' + BC)
= (A' + A)(B'C' + B'C + BC' + BC) = B'C' + B'C + BC' + BC
= B'(C' + C) + B(C' + C) = B' + B = 1
b) F(x1, x2, x3, ..., xn) = ∑mi has 2n/2 minterms with x1 and 2n/2 minterms
with x'1, which can be factored and removed as in (a). The remaining 2n1
product terms will have 2n-1/2 minterms with x2 and 2n-1/2 minterms
with x'2, which and be factored to remove x2 and x'2, continue this
process until the last term is left and xn + x'n = 1
Answer:
The answer is "Option b".
Explanation:
In the given-code variable "userEntry" is defined that prompt the user to input value and in the next step, the conditional statement is used, which checks the input value is not a number and greater than 500 with use of OR operator. if the condition is true it uses the alert box to print the message, that's why in this question except "choice b" all were wrong.
The answer is a Scroll bar, the description fits perfectly because you need to move it to see more of the content you are viewing, and it wont be completely. when the item does appear completely on screen then the bar is relatively large and there is no need for scrolling, however the opposite occurs during when you cannot see all of it.
