I believe it’s 3/10.
But even though a dice has 6 sides it’s a possibility it’s 1/2.
But from the given information it seems like it’s landing on the even side more than the odd.
I hope this helped!
Let's write the general form of the sine curve:
, where,
- A is the amplitude. Also, if A is negative, curve reflects about x axis
- B is the compression/stretching factor. It changes the period when it is a value other than 1.
- C is the phase shift. It translates curve left or right. Negative value shifts right and positive value shifts left.
- D is the vertical shift. It translates curve up or down. Negative value shifts down and positive value shifts up.
Let's check the 4 choices.
A.
Since this curve's A is -2, its amplitude is 2 and range is from -2 to 2. BUT since D value is -3, it shifts vertically 3 units down making the range from -1 to -5. Clearly choice A is not true.
B.
This graph is the graph of
shifted 3 units DOWN since D is negative. This choice isn't true.
C.
Because of the - (minus) sign in front of the function, the function is reflected about x-axis, but amplitude doesn't change. Since A value is 2, amplitude is 2. This is true.
D.
Period depends on the B value. Here, B value is 1, so period is normal as the parent function of a sine curve, which is
, NOT
. So this is not correct.
ANSWER: C is true
Answer with Step-by-step explanation:
Since we have given
n = 16
a) Describe the sampling distribution for the sample mean.
The sampling distribution of the mean is the population's mean from where the items are sampled.
It would be ![\mu](https://tex.z-dn.net/?f=%5Cmu)
b. What is the standard error?
![s=\dfrac{\sigma}{\sqrt{n}}\\\\s=\dfrac{14}{\sqrt{16}}\\\\s=\dfrac{14}{4}\\\\s=3.5](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5Cs%3D%5Cdfrac%7B14%7D%7B%5Csqrt%7B16%7D%7D%5C%5C%5C%5Cs%3D%5Cdfrac%7B14%7D%7B4%7D%5C%5C%5C%5Cs%3D3.5)
c. For 90% confidence, what is the margin of error?
Degrees of freedom = v - 1= 16-1 = 15
Using t-table, 1.753 cuts 5% level of significance in each tail.
so, Margin of error would be
![1.753\times 3.5\\\\=6.1355](https://tex.z-dn.net/?f=1.753%5Ctimes%203.5%5C%5C%5C%5C%3D6.1355)
d. Based on the sample results, create the 90% confidence interval and interpret.
So, 90% confidence interval would be
![110+6.136\\\\=116.136\\\\and\\\\110-6.136\\\\=103.86](https://tex.z-dn.net/?f=110%2B6.136%5C%5C%5C%5C%3D116.136%5C%5C%5C%5Cand%5C%5C%5C%5C110-6.136%5C%5C%5C%5C%3D103.86)
(103.86,116.136)
(A)
Solve for the first variable in one of the equations, then substitute the result into the other equation.
v=3
w=−7
(B)
Solve for the first variable in one of the equations, then substitute the result into the other equation.
t=11/6
u=1/9
Distribute on the left
2x-2+3x=3
Combine like terms
5x-2=3
Add 2 to both sides
5x=5
Divide both sides by 5
x=1
Final answer: x=1