If two sides of a triangle are 6 and 16, what is the range of the possible lengths of the third side? Enter your answer as doubl
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Answer: Any real number x as long as and
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
In this question , we have to simplify the given ratio, which is
12xy:3x
First we have to see which factor is common in numerator and denominator,
We can write 12 as 3 times 4, that is
So the common factor is 3x.
In the next step, we cancel out 3x
And that's the required simplified form .