Answer:
100,000
Step-by-step explanation:
A numerical pass code is required to open a car door.
The pass code is five digits long and uses the digits 0–9.
So, total number of possible digits will be 10
<u>Condition:-</u>
- Numbers may be repeated in the pass code.
- Pass code 5 digits long.
- digits are 0-9
Total number of possible pass code = __×__×__×__×__
For each blank space we have 10 choices to fill because digit repeated. So, every blank space 10 possible digits.
Total number of possible pass code = 10×10×10×10×10
= 10⁵
= 100,000
Hence, Total number of pass code form will be 100,000
