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kow [346]
3 years ago
6

A numerical pass code is required to open a car door. The pass code is five digits long and uses the digits 0–9. Numbers may be

repeated in the pass code. How many different pass codes exist
Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer:

100,000

Step-by-step explanation:

A numerical pass code is required to open a car door.

The pass code is five digits long and uses the digits 0–9.

So, total number of possible digits will be 10

<u>Condition:-</u>

  • Numbers may be repeated in the pass code.
  • Pass code 5 digits long.
  • digits are 0-9

Total number of possible pass code = __×__×__×__×__

For each blank space we have 10 choices to fill because digit repeated. So, every blank space 10 possible digits.

Total number of possible pass code = 10×10×10×10×10

                                                            = 10⁵

                                                            = 100,000

Hence, Total number of pass code form will be 100,000

                                                       

Alinara [238K]3 years ago
3 0
Im pretty sure it would be 45 

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