9514 1404 393
Answer:
B. 5.791
Step-by-step explanation:
The slope of the line is the coefficient of x in its equation. The equation is ...
ŷ = -74.704 +5.791x
The coefficient of x, the slope, is 5.791.
Answer:
x+y=37-------(1)
5.5x+13.5y=355.5-----(2)
Put x=37-y in eqn 2
5.5(37-y)+13.5y=355.5
203.5-5.5y+13.5y=355.5
8y=152
y=19
x=18
Step-by-step explanation:
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
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I attached a photo where I graphed these vertices in order to count the length and width. After counting the number of units between R & U I got a width of 4. And then I counted the units between S & T to get a width of 6. Using the formula to calculate the perimeter of a rectangle, P = 2(l+w). The perimeter is 20.
First I added the length plus the width, 4 + 6 and got 10. Then I did 10 x 2 which is how I got a perimeter of 20.
