Answer:
109
Step-by-step explanation:
Step-by-step explanation:
(i) Sum the forces at point M in the x direction.
∑F = ma
-T sin 30° − T sin 30° + 5 N = 0
2T sin 30° = 5 N
T = 5 N
(ii) Sum the forces on the ring in the x direction.
∑F = ma
T sin 30° − N = 0
N = 2.5 N
Sum the forces on the ring in the y direction.
∑F = ma
T cos 30° − mg − Nμ = 0
Nμ = T cos 30° − mg
2.5 μ = 5 cos 30° − 2
μ = 0.932
(iii) Sum the forces on the ring in the y direction.
∑F = ma
T cos 30° − m₁g − m₂g + Nμ = 0
m₂g = T cos 30° − m₁g + Nμ
m (10) = 5 cos 30° − 2 + (2.5)(0.932)
m = 0.466 kg
Use x+2y=8
Subtract 2y to make
x=8-2y
Plug this in to the other equation
3(8-2y)+2y=6
Distribute the 3
24-6y+2y=6
Combine like terms
24-4y=6
Solve
18/4=y, 9/2=y
Plug and solve for x
X+2y=8
X+(2*9/2)=8
X+9=8
X=-1
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Step-by-step explanation:do adc
Answer:
3
Step-by-step explanation:
1/3 + 1/3 + 1/3 = 1
This proves that there can only be 3 thirds between 0 and 1.
