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nadya68 [22]
3 years ago
15

Whats the volume? B= 37.6 cm²; h= 20 cm

Mathematics
1 answer:
Georgia [21]3 years ago
8 0

Answer:

752 cm^3

Step-by-step explanation:

Find the volume with: base x length x height

37.6 x 20 = 752

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Emily would like to buy some new
bonufazy [111]

Answer:

$14,277.80

Step-by-step explanation:

The standard formula for compound interest is given as;

A = P(1+r/n)^(nt) .....1

Where;

A = final amount/value

P = initial amount/value (principal)

r = rate yearly

n = number of times compounded yearly.

t = time of investment in years

For this case;

P = $7,400

t = 8 years

n = 4 (quarterly)

r = 9.5% = 0.095

Using equation 1.

A = $7,400(1+0.095/4)^(4×7)

A = $7,400(1.02375)^(28)

A = $7,400(1.929432606035)

A = $14,277.80

final amount/value after 8 years A =$14,277.80

6 0
3 years ago
Rewrite this expression using a positive exponent.<br> -7<br> 5
Sergio [31]

Answer:

1/5^7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve this rational equation<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bx%20%2B%204%7D%20%20%3D%20%20%5Cfrac%7B4%7
sergey [27]

Answer:

x =  - 12

C.E.: x <em>=/=</em> -4

Step-by-step explanation:

\frac{x}{x + 4}  =  \frac{4}{x + 4}  + 2 \\  \frac{x}{x + 4}  =  \frac{4 + 2x + 8}{x + 4}  \\ x = 4 + 2x + 8 \\  - x = 12 \\ x =  - 12

6 0
2 years ago
A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to buy the watch ? <br>​
Svetlanka [38]

Answer:

Rupees 891

Step-by-step explanation:

If you multiply 810 times 0.1 which is the decimal of 10%, you get 81 which you can add to 810 to get 891 which is the price the shopkeeper payed to buy the watch.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0
2 years ago
If f(x)= -3x-5 and g(x)= 4x-2 find (f+g)(x)
juin [17]

Known :

f(x) = -3x - 5

g(x) = 4x - 2

Asked :

(f+g)(x) = ...?

Answer :

(f+g)(x) = (-3x - 5) + (4x - 2)

= (-3x + 4x) + (-5 - 2)

= x + (-7)

= <u>x </u><u>-</u><u> </u><u>7</u>

So, the value of (f+g)(x) is x - 7

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

5 0
3 years ago
Read 2 more answers
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