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nadya68 [22]
3 years ago
15

Whats the volume? B= 37.6 cm²; h= 20 cm

Mathematics
1 answer:
Georgia [21]3 years ago
8 0

Answer:

752 cm^3

Step-by-step explanation:

Find the volume with: base x length x height

37.6 x 20 = 752

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The EverGlow nuclear power plant releases water into Lake Fishbegone every afternoon at 4:51 p.m. Environmental researchers are
alexandr402 [8]

9514 1404 393

Answer:

  B.  5.791

Step-by-step explanation:

The slope of the line is the coefficient of x in its equation. The equation is ...

  ŷ = -74.704 +5.791x

The coefficient of x, the slope, is 5.791.

6 0
3 years ago
During the past year, Mrs. Singh purchased 37 books at a wholesale club store. She purchased softcover books for $5.50 each and
ozzi

Answer:

x+y=37-------(1)

5.5x+13.5y=355.5-----(2)

Put x=37-y in eqn 2

5.5(37-y)+13.5y=355.5

203.5-5.5y+13.5y=355.5

8y=152

y=19

x=18

Step-by-step explanation:

5 0
3 years ago
A fence is to be built to enclose a rectangular area of 320 square feet. The fence along three sides is to be made of material t
sergeinik [125]

The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft

<h3>How to maximize area?</h3>

Let the length of the rectangular area be x feet

Let the width of the area = y feet

Area of the rectangle = xy square feet

Or xy = 320 square feet

y = 320/x  -----(1)

Cost to fence the three sides = $6 per foot

Therefore cost to fence one length and two width of the rectangular area

= 6(x + 2y)

Similarly cost to fence the fourth side = $13 per foot

So, the cost of the remaining length = 13x

Total cost to fence = 6(x + 2y) + 13x

Cost (C) = 6(x + 2y) + 13x

C = 6x + 12y + 13x

C  = 19x + 12y

From equation (1),

C = 19x + 12(320/x)

C' = 19 - 3840/x²

At C' = 0, we have;

19 - 3840/x² = 0

19 = 3840/x²

19x² = 3840

x² = 3840/19

x = √(3840/19)

x = 14.22 ft

y = 320/14.22

y = 22.5 ft

Read more about Maximization of Area at; brainly.com/question/13869651

#SPJ1

8 0
1 year ago
Find the perimeter of the rectrangle with vertices at R(-2, 3), S(4, 3), T(4, -1) and U(-2, -1).
mylen [45]
I attached a photo where I graphed these vertices in order to count the length and width.  After counting the number of units between R & U I got a width of 4.  And then I counted the units between S & T to get a width of 6.  Using the formula to calculate the perimeter of a rectangle, P = 2(l+w). The perimeter is 20.  

First I added the length plus the width, 4 + 6 and got 10.  Then I did 10 x 2 which is how I got a perimeter of 20.  

5 0
3 years ago
Need help fast due tomorrow thanks
kirill [66]

7;

2y^2-3y-1

8;

5m^2-13m+9

9;

k^2+9k

10;

2x^2-2x-5

5 0
3 years ago
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