If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
Answer:
area A(w) of the bulletin board as a function of its width, w =[100-w]*w= 100w-
Step-by-step explanation:
- let, the shape of the bulletin board is a rectangle,
- then the perimeter of it = sum of all sides
= 2[length+width] = 2[l+w]
(let l: length, w : width )
100= l+w ( dividing both the sides by 2)
so, l= 100-w
- area = length*width=l*w=[100-w]*w
- therefore,area A(w) of the bulletin board as a function of its width, w =[100-w]*w= 100w-

3x+3=192 is the equation
To solve the equation, you would subtract 3 from both sides, 3-3 cancels out, so 192-3= 189. Then, you are left with 3x=189 so you divide both sides by 3, 3x divided by 3 cancels out, so you do 189 divided by 3 which is 63.
Answer to equation: x=63
Equation: 3x+3=192
(3x^2-2x+4)+(5x^2+6x-8) - Combine like terms
8x^2+4x-4
(f+g)(x)=8x^2+4x-4