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liraira [26]
3 years ago
6

Y’all I am struggling. Help me out please I’ll give 15 points! #7

Mathematics
1 answer:
sweet [91]3 years ago
6 0
Since the angles in triangle ACM indicate that it is a 30-60-90 triangle, we know that the other two sides of triangle ACM are 20 and 10 (30-60-90 triangles have a very specific side coefficient). This means that the sides of this triangle have side lengths 40, 10, and 20\sqrt{3}. Adding these together you get 50+20\sqrt{3}. Hope this helps!
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Can someone help me Domain and range I would mark the brainlist ​
Ivenika [448]

Answer:

b

Step-by-step explanation:

i did it yesterday

6 0
3 years ago
Simplify 2(x - 4) + 7(x + 2).
Sauron [17]

Answer:

9x+6

Step-by-step explanation:

2(x-4)= 2x-8

7(x+2)= 7x+14

2x-8+7x+14

clt

9x6

3 0
3 years ago
Determine the mean of the numbers 6, 17, 22, 28, and 37.
Kipish [7]
To find the mean or the avg you add up all the numbers you have and then divide by how many numbers you added together in this case 5

6+ 17+22+28+37=110

\frac{110}{5} =22

so the mean is 22, hope this helped you!
4 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
In 2000, the number of students enrolled at Arlington Country Day School was 823 students. In 2010, the population was approxima
vivado [14]
705 - 823 = -118

-118/823 = -0.143 = 14.3% decrease
5 0
3 years ago
Read 2 more answers
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