The output would depend on the input so relating this to the question, the input is the time (in minute) and the output is the amount of water left in the tank
We can give a letter 't' for the time, the input, and f(t) for the output
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The original amount of water in the tank is 10450, so this will be the fixed constant.
The amount of water lost per minute is 270 so this will be the term that varies depends on the variable of time, we write this as 270t
The function is given f(t) = 10450 - 270t
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Given, t = 10
f(10) = 10450 - 270(10)
f(10) = 7750 ml
2:3 is equivalent to 0.666 repeating
If you have any further questions feel free to ask.
Hope this helps.
Answer:
25
Step-by-step explanation:
you just multiple 5 times 5
Answer:
The correct answer is if you want no roots in the denominator, the correct answer is 
* ![\sqrt[3]{2y^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2y%5E%7B2%7D%20%7D)
Step-by-step explanation:
The mistake is that you can't take a cube root of a square at step 3 when 
is taken out.
Applying the angles of intersecting secants theorem, the measures of the arcs are:
m(KL) = 20°; m(MJ) = 80°.
<h3>What is the Angles Intersecting Secants Theorem?</h3>
When two secants intersect and form an angle outside the circle, the measure of the angle formed is half the positive difference of the measures of the intercepted arcs.
Given the following:
m∠MEJ = 1/2(MJ - KL)
30 = 1/2(MJ - KL)
60 = MJ - KL
KL = MJ - 60
m∠MFJ = 1/2(MJ + KL)
50 = 1/2(MJ + MJ - 60)
100 = 2MJ - 60
2MJ = 100 + 60
2MJ = 160
MJ = 160/2
MJ = 80°
KL = MJ - 60 = 80 - 60
KL = 20°
Thus, applying the angles of intersecting secants theorem, the measures of the arcs are:
m(KL) = 20°; m(MJ) = 80°.
Learn more about angles of intersecting secants theorem on:
brainly.com/question/1626547
