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One set of markers cost x dollars. How much would set of makers and crayons cost together

inysia [295]

Answer:

x+y

Step-by-step explanation:

Let's pretend the value of the crayon's is 'y'. The value of the markers is 'x'. If we add them together, we get x+y. This is because we do not know the value of each variable.

Hope this helps! Have a nice day <3

3 0

3 years ago

3. In the fig. AD = DC and AB = BC. Prove that ΔADB = ΔCDB<br>

xxMikexx [17]

Answer:

The two column proof is presented as follows;

The given parameters are;

$\overline {AD}$ = $\overline {DC}$ and $\overline {AB}$ = $\overline {BC}$

Statement ${}$ Reason

$\overline {AD}$ = $\overline {DC}$ and $\overline {AB}$ = $\overline {BC}$ ${}$ Given

$\overline {BD}$ ≅ $\overline {BD}$ ${}$ Reflexive property

$\overline {BD}$ = $\overline {BD}$ ${}$ By the definition of congruency

ΔADB ≅ ΔCDB ${}$ By Side-Side-Side (SSS) rule of congruency

ΔADB = ΔCDB ${}$ By the definition of congruency

If the three sides of one triangle are congruent to the corresponding three sides of another triangle, then both triangles are said to be congruent according to the SSS rule of congruency

Step-by-step explanation:

7 0

3 years ago

Is there enough information to prove that the triangles are congruent?

olasank [31]

Answer:

Yes, there is enough information to prove that the triangles are congruent.

SAS POSTULATE

Step-by-step explanation:

$In\:\triangle ABC \: and \triangle XYZ\\$

$AB\cong XY..... (given) \\$

$\angle ABC \cong\angle XYZ\\(each \: 90\degree) \\$

$BC\cong YZ..... (given) \\$

$\therefore \triangle ABC \cong \triangle XYZ\\(SAS\: postulate)$

7 0

3 years ago

Read 2 more answers

Please help Ill give brainy pleas help please

MissTica

Answer:

m=0

Step-by-step explanation:

it just is as there is no change

3 0

2 years ago

The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5).

melamori03 [73]

<h3>Answer:</h3>

Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

<h3>Explanation:</h3>

The problem statement tells you the transformation is ...

... (x, y) → (x, -y)

Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.

Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)

An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.

So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.

6 0

4 years ago