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quester [9]
3 years ago
15

Solve for a. ab + c = d​

Mathematics
2 answers:
inessss [21]3 years ago
5 0
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ ab + c = d

Subtract c from both sides:

ab = d - c

Divide both sides by b

a = (d - c) / b

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

SIZIF [17.4K]3 years ago
5 0

Answer:

a=d-c/b

Step-by-step explanation:

ab+c=d you subtract c

ab=d-c then you divide by b

a= d-c/b

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Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

ABCD and EGFH are two trapezoids.

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Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

3 0
3 years ago
Nine pounds of beans are distributed equally into 4 bags to give out at the food bank. How many pounds of beans are in each bag?
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Its 7 hours and 15 minutes
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What is q? For this 30 and 60, 90 angle?
Effectus [21]
30 60 90 triangle
ratio of short leg : long leg = a : a√3

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