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yuradex [85]
3 years ago
10

Find the z-score that has 62.8% of the distribution's area to its right.

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0
<span>The best and easiest way to get it is by using a TI calculator and i hope you can have it, then you can type in the next: invnorm(1 - 0.628) What you are doing is that you are subtracting the probability from 1 because the invnorm function finds the z-score given the probability to the left of the z-score. I think that can help you. </span>

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From my understanding of a triangle's centroid, it divides an angle bisector into parts of 2/3 and 1/3. In the given problem, these divisions are NS and SR. Therefore, twice SR would be equal to NS. From here, we can get the value of X, to solve for SR.

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