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Elodia [21]
3 years ago
15

Solve: y+8=2=? Please explain or put how did you get the answer. Ty

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

y+8=2

Move +8 to the other side. Sign changes from +8 to -8.

y+8-8=2-8

y=-6

Answer: y=-6

kramer3 years ago
8 0

For this case we have the following equation:

y + 8 = 2

We must clear the value of the variable "and":

If we subtract 8 on both sides we have:

y + 8-8 = 2-8

Different signs are subtracted and the sign of the major is placed:

y = -6

So, the value of y is -6

Answer:

y = -6

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stepladder [879]
Y = 3

Exp:

10 + 12y = 2y + 40
- 2y = - 2y

10 + 10y = 40
-10 -10

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/ 10 / 10

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4 0
3 years ago
What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.
dangina [55]

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = \frac{x^2+6x+9}{3x+15}

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

6 0
3 years ago
Math<br><br><br> is my answer correct??
matrenka [14]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution ~

The given points are : (-7 , -4) and (1 , 1)

now, let's use distance formula to find the distance between them !

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:\sqrt{(x_2 - x_1)² +( y_2 - y_1)² }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{( - 7 - 1) {}^{2}  + ( - 4  - 1) {}^{2} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{( - 8)² +(  - 5)² }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{64 + 25}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{89}

3 0
2 years ago
What is the center and radius of the circle? *<br> (x - 2)² + (y – 9)^2= 4
Rudiy27

the center is (2,9)

and the radius is 2

5 0
3 years ago
Can someone assist me with this, I'm having problems with this
nirvana33 [79]
It’s true!! Hope this helped!!!!
8 0
3 years ago
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