Find the magnitude of the vector. (-2,-7)

Mathematics

2 answers:

Vikki [24]2 years ago

4 0

Answer:

Step-by-step explanation:

nevsk [136]2 years ago

3 0

Answer:

$\sqrt{53}$

Step-by-step explanation:

$\begin{pmatrix}-2&-7\end{pmatrix}\\=\sqrt{\left(-2\right)^2+\left(-7\right)^2}\\\\$

Then you need to simplify:

$=\sqrt{2^2+\left(-7\right)^2}\\=\sqrt{2^2+7^2}\\=\sqrt{4+7^2}\\=\sqrt{4+49}\\=\sqrt{53}$

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A segment with endpoints (5,8) and (-6,8) is rotated around the origin. How long will the new segment be?

Gekata [30.6K]

The segment was only rotated, not changed. It would be the same length as the original.

To find the length, use the distance formula.

$\sqrt{ {(x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$
(5, 8) would be point 1.

(-6,8) would be point 2.

Plug them into the formula.

$\sqrt{( { - 6 - 5)}^{2} + ( {8 - 8)}^{2} }$
Simplify.

$\sqrt{( { - 11)}^{2} + ( {0)}^{2} }$
$\sqrt{121 + 0}$
$\sqrt{121}$
Square root this answer.
$\sqrt{121} = + or - 11$
Negative distances aren't possible, so your answer is 11.

Hope this helped!

:)

5 0

3 years ago

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xenn [34]

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astra-53 [7]

Answer:

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Step-by-step explanation: