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quester [9]
3 years ago
14

Solve.

Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer:

-3 ± 2\sqrt{3} = x

Step-by-step explanation:

x² + 6x + 9 = 12 → x² + 6x - 3

Since this Quadratic Expression is unfactorable, apply the <em>Quadratic</em><em> </em><em>Formula</em>:

x = -b ± \frac{\sqrt{{b}^{2} - 4ac}}{2a}

-6 ± \frac{\sqrt{{6}^{2} - 4(1)(-3)}}{2(1)} =   -6 ± \frac{\sqrt{36 + 12}}{2} = -6 ± \frac{\sqrt{48}}{2} \\ \\ -3 ± 2\sqrt{3}

√48 = √[3 × 16] = 4√3

½[4√3] = 2√3

Then attach half of -6 to it as well [-3]:

-3 ± 2√3

I am joyous to assist you anytime.

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The graph of a function is shown below. find the following, g(10), g(-3)
Rzqust [24]

Answer:

g(5x)=0

Step-by-step explanation:

Given that g(x)=4

From the graph when x=-2 then g(x)=4

Hence 5x=-10

Now from the graph

g(-10)=0

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2 years ago
Need help please extra points?!?!!?!<br><br><br> Really need help
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Answer:

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Step-by-step explanation:

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3 years ago
12=2(q-7)<br> Solve for q
RUDIKE [14]

Answer:

not sure just want points

Step-by-step explanation:

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2 years ago
Read 2 more answers
Evaluate each expression if a = 6, b = 3, and c = 2.
My name is Ann [436]

Answer:

1. 18

2. 6

3. ?

4. 3

5. 4

6. 1

7. 5

Step-by-step explanation:

1. 6 x 3 = 18

2. 2 + 4 = 6

3. ( I cant read the problem)

4. 6 - 3 = 3

5. 2 x 2 = 4

6. 3 ÷ 3 = 1

7. 6 - 1 = 5

8. 6 + 2 = 8

7 0
3 years ago
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

now, we can use factor formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can use above formula

we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

27x^3-1=(3x-1)(9x^2+3x+1)=0

and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

now, we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can plug values

and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

5 0
3 years ago
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