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matrenka [14]
3 years ago
15

12=2(q-7) Solve for q

Mathematics
2 answers:
RUDIKE [14]3 years ago
3 0

Answer:

not sure just want points

Step-by-step explanation:

salantis [7]3 years ago
3 0

Answer:

q=13

Step-by-step explanation:

13-7=6

6*2=12

Therefore q=13

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Find the diameter of a circle with a radius of 5.5cm
adelina 88 [10]
As diameter is twice of the radius , so diameter= 2multiplied by 5.5 that is 11.0 cm

6 0
3 years ago
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Write an equation in point-slope form and slope-intercept form
liq [111]

Answer:

point-slope form: y - 1 = -4/5(x - 8)    

slope-intercept form:  y = -4/5x + 7.4

Step-by-step explanation:

Find slope using the points (8, 1) and (-2, 9):

  m = (y₂ - y₁) / (x₂ - x₁)

      = (9 - 1) / (-2 - 8)

      = 8 / -10

  m = -4/5

Find y-intercept using slope m from above and anyone of the given points, let's use (8, 1):

  y = mx + b

  1 = -4/5(8) + b

  1 = -6.4 + b

   b = 7.4

Use slope m and y-intercept b above to form equation of line in slope-intercept form:

  y = mx + b

  y = -4/5x + 7.4

For point slope form use slope m from above and a point, again let's use (8, 1):

  y - y₁ = m(x - x₁)

  y - 1 = -4/5(x - 8)    

6 0
3 years ago
A number, y, is equal to the difference of a larger number and 3. The same number is one third of the sum of the larger
Mnenie [13.5K]

Answer:

  • Set the larger number as x

"<em>A number, y, is equal to the difference of a larger number and 3.</em>"

y=x-3

<u>You can rearrange this equation to find the matching answer choice:</u>

y-x=-3\\x-y=3

"<em>The same number is one third of the sum of the larger number and 9.</em>"

y=\frac{1}{3} (x+9)

<u>You can rearrange this equation to find the matching answer choice:</u>

y=\frac{1}{3} x+3\\3y=x+9\\3y-x=9\\x-3y=-9

5 0
3 years ago
For what values of h are the vectors [Start 3 By 1 Matrix 1st Row 1st Column negative 1 2nd Row 1st Column 4 3rd Row 1st Column
Bogdan [553]

Answer:

The set is linearly dependent for every value of h.

Step-by-step explanation:

Recall that a set of vector {a,b,c,d} is a linearly dependent set of vectors if any of the vectors can be written as a linear combination of the other ones.

We are given the following vectors.a=(-1,4,6), b=(5,2,-3), c=(3,-5,-4), d=(12,-20, h). At first, we will check if a,b,c are linearly independent. To do so, we will calculate the following determinant (the procedure of the calculation is omitted).

\left|\begin{matrix}-1 & 5 & 3 \\ 4 & 2 & -5 & \\ 6 & -3 & -4\end{matrix}\right| = -119\neq 0

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3 0
3 years ago
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Airida [17]

C

a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment

using the midpoint formula

M = [\frac{1}{2} (0 + 20 ), \frac{1}{2} (15 + 0)] = (10, 7.5 )


5 0
3 years ago
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