Question

B) Write an equation of the line that crosses the graph of f(x) at x=-1 and x=2​

Answer 1

Answer:

Step-by-step explanation:

let it passes through (-1,y1) and (2,y2)

$slope=\frac{y2-y1}{x2-x1} =\frac{y2-y1}{2-(-1)} =\frac{y2-y1}{3} \\eq. ~of~line~is~\\y-y1=\frac{y2-y1}{3} (x+1)\\3y-3y1=xy2-xy1+y2+y1\\3y=(y2-y1)x+y2+4y1$