Answer:
a
Step-by-step explanation:
the vertex is (1,-1)
y = −3x^2 + 6x − 4
the vertex is at
h= -b/2a where ax^2 +bx+c
h= -6/2(-3)
h= -6/-6
h=1
substitute this in to find the y value
y = -3(1)^2 +6(1)-4
y = -3+6-4
y = -1
