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r-ruslan [8.4K]
2 years ago
7

The third term in an arithmetic sequence is 58 and the fifth term is 90. if the first term is a1, which is an equation for the n

th term of this sequence? 1. an = 8n + 10 2. an = 8n − 14 3. an = 16n + 10 4. an = 16n − 38

Mathematics
1 answer:
kiruha [24]2 years ago
3 0
The third term in an arithmetic sequence is 58 and the fifth term is 90. if the first term is a1, which is an equation for the nth term of this sequence?
1. an = 8n + 10
2. an = 8n − 14
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆3. an = 16n + 10
4. an = 16n − 38

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If A = {w.a, t,c, h, d, 0,8} and U = {a,b,c,d, e, f, g, h, L.), k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z), find A'
Ugo [173]
Adcdefghijklmnopqrstuvwxyz
6 0
3 years ago
Your family has a cable television package that costs $40.99 per month. Pay-per-view movies cost $3.95 each. Your family budgets
ELEN [110]

Answer:

3 movies

Step-by-step explanation:

55$-40.99$= 14.01$ left to spend on movies

$14.01/$3.95=3.54

Which means you can buy 3 movies.

5 0
3 years ago
A truck rental company rents a moving truck One Day by charging $39 + 0.09 per mile write a linear equation that relates the cos
Ivanshal [37]

Answer:

(a)\ c(x) = 39 + 0.09 x

(b)\ \$53.4

Step-by-step explanation:

Given

Base\ Charge = \$39

Rate = 0.09 per mile

Solving (a): Linear Equation

The total charges (c(x)) is: the base charge + the rate * number of miles (x).

So, we have:

c(x)= 39 + 0.09 * x

c(x) = 39 + 0.09 x

Solving (b): Cost of rent, if miles = 160

This implies that x = 160

So, we have:

c(x) = 39 + 0.09 x

c(160) = 39 + 0.09 *160

c(160) = 39 + 14.4

c(160) = 53.4

7 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
In the expression (ax+b)*(cx^2+dx+e), find two set of values of a,b,c,d and e so that the coefficient of x^3and x terms after ex
Brilliant_brown [7]

Answer:

2, 0, 2, 3, 5

1, 2, 4, 0, 5

Step-by-step explanation:

(ax + b)(cx² + dx + e)

acx³ + adx² + aex + bcx² + bdx + be

2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0

4x³ + 6x² + 10x

a = 2

b = 0

c = 2

d = 3

e = 5

1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10

4x³ + 8x² + 10x + 10

a = 1

b = 2

c = 4

d = 0

e = 5

7 0
2 years ago
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