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r-ruslan [8.4K]
3 years ago
7

The third term in an arithmetic sequence is 58 and the fifth term is 90. if the first term is a1, which is an equation for the n

th term of this sequence? 1. an = 8n + 10 2. an = 8n − 14 3. an = 16n + 10 4. an = 16n − 38

Mathematics
1 answer:
kiruha [24]3 years ago
3 0
The third term in an arithmetic sequence is 58 and the fifth term is 90. if the first term is a1, which is an equation for the nth term of this sequence?
1. an = 8n + 10
2. an = 8n − 14
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆3. an = 16n + 10
4. an = 16n − 38

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Twice a number plus twice a second number is 310. The difference between the numbers is 55. Find the numbers by writing and solv
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<em><u>Solution:</u></em>

Let "x" be the first number

Let "y' be the second number

Twice a number plus twice a second number is 310

Therefore,

twice of x + twice of y = 310

2x + 2y = 310 ---------- eqn 1

The difference between the numbers is 55

x - y = 55 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 2,

x = 55 + y ------ eqn 3

<em><u>Substitute eqn 3 in eqn 1</u></em>

2(55 + y) + 2y = 310

110 + 2y + 2y = 310

4y = 310 - 110

4y = 200

<h3>y = 50</h3>

<em><u>Substitute y = 50 in eqn 3</u></em>

x = 55 + 50

<h3>x = 105</h3>

Thus the numbers are 105 and 50

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