8.6 + 5.6x - 1.5 = 40.7
2 answers:
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Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
A = 115 + 1/2 (p + s)
you subtract 115 from both sides, and you get
A - 115 = 1/2 (p + s)
now you multiply by 2 on both sides, and you get
(A - 115) * 2 = p + s NOTE: I DISTRIBUTED 2 IN THE FOLLOWING EQUATION
now you subtract p on both sides to get s by itself and you get
2A - 230 - p = s
so the final answer is .......
you subtract 115 from both sides, and you get
A - 115 = 1/2 (p + s)
now you multiply by 2 on both sides, and you get
(A - 115) * 2 = p + s NOTE: I DISTRIBUTED 2 IN THE FOLLOWING EQUATION
now you subtract p on both sides to get s by itself and you get
2A - 230 - p = s
so the final answer is .......